5) One silver electrode in 246 ml of 0.100 M AgNO3 solution and one in 188 ml of 0.100 M Mg(NO3)2 solution A galvanic cell was formed by dipping the magnesium electrode. a) E value of the cell at 25°C calculate. WMAN b) Since the current is generated at the silver electrode until 2.10 g of silver is collected, cell potential, find the value of E. EºMg2+/Mg = -2,37 V; EºAg+/Ag = 0,800 V
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