Trial 1Trial 2concentration of NaOH (M).100.100volume of NaOH added at equivalence point as determined by thepH plot (mL)2424volume of NaOH added at equivalence point as determined by thefirst derivative plot (mL)X23volume of NaOH added at equivalence poi

匿名用户 最后更新于 2021-12-01 19:31 化学类Chemistry

Trial 1

Trial 2

concentration of NaOH (M)

.100

.100

volume of NaOH added at equivalence point as determined by thepH plot (mL)

24

24

volume of NaOH added at equivalence point as determined by thefirst derivative plot (mL)

X

23

volume of NaOH added at equivalence point as determined by thesecond derivative plot (mL)

X

25

1. Calculate the moles of NaOH delivered at the equivalencepoint as determined by the second derivative plotfor your careful trial, then enter the values in Table 2.

2. Calculate the number of moles of HCl as experimentallydetermined by the titration into Table 2

3. Calculate the concentration of the original HCl solution forthen enter the values in Table 2.

Trial 2

moles of NaOH at equivalence point

moles of HCl

concentration of original HCl solution (M)

Volume HCL is 10 ml

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