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The Solubility Product Constant(Ksp) Of Lead(II) Iodide Is 1.4 X 10 At 25°C. Calculate AG°for The Dissociation Of Lead(II) Iodide In -8 Water. PbIz(s) = Pb2+ (aq) + 21+ (aq) QUESTION 3 DOK 2 NO STANDARD Could There Ever Be A Reaction When AG Is Greater Th

匿名用户 最后更新于 2021-12-01 19:31 化学类Chemistry

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The solubility product constant(Ksp) of lead(II) iodide is 1.4 x 10 at 25°C. Calculate AG°for the dissociation of lead(II) iodide in -8 water. PbIz(s) = Pb2+ (aq) + 21+ (aq)
QUESTION 3 DOK 2 NO STANDARD Could there ever be a reaction when AG is greater than 0 and Keq is greater than 1? Why or why not?

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