Application Questions: 17. Two taster parents produce both taster and non-taster children. What must be the genotype of both parents? 18. Two non-taster parents can only have non-taster children. Why? 19. Can two homozygous taster parents have non-taster children? Why or Why not? or Dihybrid Cross (probability of inheriting two non-linked traits, in this case from heterozygous parents) A woman with heterozygous genotypes for A-type blood (AO) and Rh positive blood factor (Rt) and a man who has heterozygous genotypes for B-type blood (BO) and Rh positive blood factor (Rr) decode to have a child together. 20. Can these two parents (A-type blood and Rh positive + B-type blood and Rh positive) have an O-type blood Rh negative child? Circle your answer here: Yes No How to figure this out? Use an extended Punnett Square (dihybrid crosses) to determine the probabilities of blood type and Rh factor for their child. Mother's possible genotype combinations: AR, OR, Ar, Or Father's possible genotype combinations: BR, OR, Br. Or Cross-factor these possibilities. You should have four letter combinations in each box. A few boxes have been completed to get you started and stay on track. (dad) BR OR Br Or (mom) AR ABRR OR OORR Ar ABrr Or
Remember that whenever a dominant allele is present, the dominant phenotype will be what you see! You must have two recessive alleles in order for the recessive phenotype to be visible! % % What is the probability that their child will be AB-type blood and Rh positive? What is the probability that their child will be A or B-type blood and Rh positive? % What is the probability that their child will be O-type blood and Rh negative?