-9 . X1 Let L: R3 R3 be a linear operator such that LC x2 X₂ - X1 X1 then Ker(2) spanned by: ut of Select one: uestion a. {e1,e2,ez) b. {(1,03) C. {ez, e3} d. 1 {| 1 )
710 To solve y" – 2y' +2y=e'sect one found the complementary solution is e'l cost + casint) then the particular solution is: ut of Select one: a. etsint + e cost tant question O b. 4te'sint O C. 4te cost d. te'sint + e cost In cost|
en 11 Let ty' +(t + 1)y=2t e then the integrating factor equal: d Select one: a. out of tel question O b. t+e C. t + In|t| d. t