Given that ABC is an Isosceles triangle with AB AC and AD bisecting ZBAC, which of the following proves that A BAD 2A CAD? A B
1. AB – AC (Given) 2. AD bisects ZBAC. (Given) 3. BD – AD (Def. of bisect) 4. BD – DC (Sym. Prop of =) 5. A BAD 2A CAD (SAS Steps 1, 3, 4) B 1. AB – AC (Given) 2. AD bisects ZBAC. (Given) 3. BD – DC (Def. of bisect) 4. AD = AD (Reflex. Prop of =) 5. ABAD 2A CAD (SAS Steps 1, 3, 4)
D 1. AB AC (Given) 2. AD bisects ZBAC. (Given) 3. ZBAD - ZCAD (Def. of bisect) 4. AD - AD (Reflex. Prop of =) 5. A BAD ZA CAD (SAS Steps 1, 3, 4) D 1. AB – AC (Given) 2. AD bisects ZBAC. (Given) 3. ZABD - ZACD (Def. of bisect) 4. AD 2 BD (Sym. Prop of =) 5. A BAD ZA CAD (SAS Steps 1, 3, 4)