Consider the series 3 n=1 m+ In order to address the convergence/divergence of this series we will use the comparison test. From the options below, select the appropriate statement to begin the argument. We will find g(n) such that 0 S 3 Vn+4n Sg(n), for all n > 1, to prove that the above series diverges We will find g(n) such that 0 1, to prove that the above series diverges. We will find g(n) such that 0 1, to prove that the above series converges. We will find g(n) such that 0 3 1, to prove that the above series converges. Vm+4 A suitable expression for g(n) is g(n) = diverges as where the series 9(n) n=1 (点击获得列表)