Evaluate √e−1 - √e−1 ∫1−x Ln(x2+1)-x 2x3e(x+y)sin(e(x+y))dxdy - 道道学堂问答

Evaluate √e−1 - √e−1 ∫1−x Ln(x2+1)-x 2x3e(x+y)sin(e(x+y))dxdy

匿名用户最后更新于 2021-12-01 19:10 数学类Mathematics

Evaluate √e−1 - √e−1 ∫1−xln(x2+1)-x2x3e(x+y)sin(e(x+y))dxdy

2x’ex+y sin(ex+y)dxdy

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