26 (2 Points) [1 1 1] Find the inverse of A= 2 1 12 2 3] 1/? 1 0 1 11 1 1 -1 A) 4 2 1 -1 0 B) 1 1 1 2 2 3 0. -1 CI-2 1-2 -1 -1 -2 D) does not exist -1 -3) Enter your math answer
24 (2 Points) 2 If L: R?—- R’be defined by 2 (191) , , L - 3 . Then z([ 3"))= = lo A) 3 B) 3 8 C) -3 31 81 D) -31 Enter your answer
20 (2 Points) The matrix A=[ ] has two eigenvalues 2s=0 and 12–6. Which of the following an eigenvector of A corresponding to 21=0. A. [1] B. (0) c.[3] D. [12] Enter your math answer
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