1 + 2k3 [X1] = K1[A] – K4[X]2 + K2[X1][A] 1+ Kz + K5[Xi] [X1] = K1[A] – K4[X1]+ K2[X*][A]{1 + 2k3(1 + K3 +k5[Xi])-1} [X1] = K1[A] – K4[X1]+ K2[X*][A]{1 + 2k3(1 + K3 +k5[Xi])-1}

匿名用户 最后更新于 2021-12-01 18:55 其他 All Others


Express in terms of [X*1]

1 + 2k3 [X1] = k1[A] – k4[X]2 + k2[X1][A] 1+ kz + k5[Xi] [X1] = k1[A] – k4[X1]+ k2[X*][A]{1 + 2k3(1 + k3 +k5[Xi])-1} [X1] = k1[A] – k4[X1]+ k2[X*][A]{1 + 2k3(1 + k3 +k5[Xi])-1}

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