5) One Silver Electrode In 246 Ml Of 0.100 M AgNO3 Solution And One In 188 Ml Of 0.100 M Mg (NO3)2 Solution A Galvanic Cell Was Formed By Dipping The Magnesium Electrode. A) E Value Of The Cell At 25 °C Calculate. B) Since The Current Is Generated At The

匿名用户最后更新于 2021-12-01 18:55 其他 All Others

5) One silver electrode in 246 ml of 0.100 M AgNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2 solution A galvanic cell was formed by dipping the magnesium electrode. a) E value of the cell at 25 °C calculate. b) Since the current is generated at the silver electrode until 2.10 g of silver is collected, cell potential, find the value of E. EºMg2+/Mg = -2,37 V; EºA Ag+/Ag = 0,800 V Il

已邀请:

1 回答

登录查看答案

5) One Silver Electrode In 246 Ml Of 0.100 M AgNO3 Solution And One In 188 Ml Of 0.100 M Mg (NO3)2 Solution A Galvanic Cell Was Formed By Dipping The Magnesium Electrode. A) E Value Of The Cell At 25 °C Calculate. B) Since The Current Is Generated At The

与内容相关的链接

1 回答