Procedure I - Test Solution 1: Water Trial Starting Volume Of Test Solution (L) Starting Volume Of Water (L) Final Volume Of Test Solution (L) Final Volume Of Water (L) Difference In Final Volumes (L) 1 1.28 1.38 1.33 1.33 0 2 1.28 2.12 1.70 1.70 0 [1] Gi

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Procedure I - Test Solution 1: Water

Trial

Starting Volume of Test Solution

(L)

Starting Volume of Water

(L)

Final Volume of Test Solution

(L)

Final Volume of Water

(L)

Difference

in Final Volumes

(L)

1

1.28

1.38

1.33

1.33

0

2

1.28

2.12

1.70

1.70

0

[1] Given that the final heights (and volumes) are the same forthe water and test solution, what can you conclude about the amountof solutes in these two solutions? Explain your reasoning.

[2] As discussed in the Background material, water is animportant biological molecule. Do you expect water to continue toflow across the semipermeable; lipid bilayer after osmoticequilibrium is reached? Why or why not?

Procedure II - Test Solution 2: Guanine solution

Trial

Starting Volume of Test Solution

(L)

Starting Volume of Water

(L)

Final Volume of Test Solution

(L)

Final Volume of Water

(L)

Difference

in Final Volumes

(L)

1

1.28

1.35

0.88

1.75

-0.87

2

1.28

2.03

1.22

2.09

-0.87

[3] Why did the height (and volume) change in the test solution?What is the basis for the increase in the volume in the testsolution?

[4] What do you think would happen if both starting volumes werethe same? Test your hypothesis by doing a data run. Explain yourobservation.

[5] Why is the difference in final volumes the same (or veryclose to the same) for both trials?

Procedure III - Test Solution 3: Cytochrome C solution

Trial

Starting Volume of Test Solution

(L)

Starting Volume of Water

(L)

Final Volume of Test Solution

(L)

Final Volume of Water

(L)

Difference

in Final Volumes

(L)

1

1.28

1.52

1.07

1.73

-0.66

2

1.28

2.05

1.33

2.00

-0.67

[6] Based on your data and observations from procedure II andprocedure III, which solution has the highest concentration?Explain your answer.

[7] Concentration Calculation: Using your Trial 1 data fromprocedure II and procedure III, and the known concentration ofguanine (see Activity Form tab), calculate the concentration of thecytochrome c solution. Hint: See the Summary of Needed Formulassection under the Background tab and information found under theActivity Form tab.

SolutionCompoundmMolarConcentration
(mmol/L)
solution2guanine0.170
solution3cytochrome cto bedetermined

Note: Concentration is a measure of the amount of a substancecontained per unit volume. A commonly used unit for the amount ofsubstance is the mole (mol). When used along with the metric unitfor volume, concentration may be expressed in mole per liter(mol/L). Often, for the small concentrations associated withbiological systems, millimole per liter (mmol/L) may be used toexpress concentrations. One millimole is 1/1000 of a mole.

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