Problem 2) Static Equilibrium with friction 9 Figure A) Figure B) A homogeneous box (mass m, side length a and b) is standing on an inclined plane as shown in the LPlus figure A. The box is loaded by a unknown Force F at the top left corner. The friction coefficient between the box and the wedge is po. - The correct Free Body Diagram is given in figure 8). -The unknown reaction forces (RN) as well as the position of the normal force (c) are already calculated and given in Figure C) 1 2d) Calculate the upper limit for the force in Newton, such that no sliding occurs. Fmax Sliding = N ME round the results to one place after the decimal point. Example: 3.145 => 3.1 Example: 3.154 => 3.2 2d) Calculate the upper limit for the force in Newton, such that the box is not tipping over to the right (clockwise) LP Fmax Tilting = N Figure C) round the results to one place after the decimal point. Example: 3.145 => 3.1 Example: 3.154 => 3.2 Figure D Given properties: R = F + sin().m.g N = cos(p).m.g -F+b+cos($).m.g.-sin($).m.g. COS()-mog (1) (2) 2d) Consider now that F is increas slowly from O N to 100 N. Which of the following statements is correct? a= 0.8 m b C= (3) b = 1.0 m The box m = 30 kg 9.81 m/s = 0.5 (p= 20° Hanna Alnagar WS2021 Mech2